Elements of geometry, containing books I and II with exercises and notes (1882)
Smith, J. Hamblin (James Hamblin), 1829-1901 · Toronto : Gage · leaf 114
us : Bisect z ABC by the straight line BE, meeting AC in E.Draw ED and EF parallel to BC and AB respectively.Then DBFE h. the rhombus required. (See Ex. 4, p. 59,) Books I. & II.] SOLUTIOX OF PROBLEMS. Ex. 3. To (htirminc the j^oint in a given straight line, atwhich straight lines, drawn from… … We then reason thus : If BP were produced to some point A , z CPA, being= / BPD, will be= L APC.Again, if PA be made equal to PA, A A will be bisected by CP at right angles. This is a fact from which we can work backward, and findthe steps necessary for the solution of the problem ; thus ; From A…
Geometry
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