Advanced geometry for high schools : synthetic and analytical (1919)
McDougall, A. H. (Alexander Hiram), 1859-1946 · Toronto : Copp, Clark · leaf 153
e st. line Ax + By + C = 0as the origin. 47. Sign of the Perpendicular. It follows fromthe preceding article that, if the positive sign isalways taken for -j/A2 + B-, when the sign ofA£C, + B//, + C /A2 4- B2is the same as the sign of C, the point (xv yx) andthe origin are on the same side of the… … zs between the lines Ax 4- b</ 4- c = 0 and Axjr 4-Btf 4- Cx = 0. PERPENDICULARS 49 The Is to the st. lines from any point P (x, y) oneither bisector are equal to each other, .*. the required equations are Ax + By + c = ^ Ajx+_B1y_+_c1 ^A2 + B2 V Ax2 + Bf If the equations are so written that C…
Geometry · Geometry, Analytic
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