The Civil engineer and architect's journal, scientific and railway gazette (1839)
London : [William Laxton] · leaf 87
responding rule will be—Multiply theotal weight of the half arch by the horizontal distance of its centreof gravity from the springing of the intrados, and divide the productby the greatest height of the arch, or the height of the vertex of theextrados above the springing of the intrados. Having… … horizontal pressures from the effect of the loading: if it did, the hori-zontal thrust P at d, would no longer be equal to the P at a, fig. 1. Let us take the case of a half arch,a a d d, supporting a mass of masonryabove it, as in the accompanying figure2. This would be the case of a…
Architecture · Civil engineering · Science
Internet Archive · Boston Library Consortium · Public Domain Mark 1.0. Free to use for anything.