A complete and practical solution book for the common school teacher (1899)
Fairchild, J[ohn] T[heodore] [from old catalog] · Crawfis College, Ohio, The author · leaf 153
t., and the per-pendicular is 65 ft.: required the base, without squaring either of thegiven numbers. Solution.[ (97 + 65) (97 — 65) ] = 72 ft., the base. PROBLEM 305.How long a ladder will be required to reach a window 40 feet fromthe ground, if the distance of the foot of the ladder from the wall… … FIG. 7. MENSURA TWN. 139 (3) Then we have 25*2 + x* — 402. (4) Whence, 5* = 40.824829 ft., the required length. Note.—This solution was prepared by the author for the SchoolVisitor. PROBLEM 306. A right-angled triangle, altitude 7 ft., and hypothenuse 25 ft., hasthe same area as a rectangle whose…
Arithmetic · Geometry
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