A complete and practical solution book for the common school teacher (1899)
Fairchild, J[ohn] T[heodore] [from old catalog] · Crawfis College, Ohio, The author · leaf 202
. (19) Multiply the diameter of the circle by .96426-j-, and the result will be the length of the chord. (20) . . .96426X50=48.21300 ft.=GH. PROBLEM 382.A circular field 80 rd. in diameter, is divided into three equal partsby two parallel fences: find length of fences, and the distance each isfrom… … 4 FIG. 6K. k, or0=15c o (4) Angle KOT=X=90°. (5) .-. A— 0=74°3813=KOB (6) Sin^= .96426+. (7) .. AB=DT the diameterX.96426-J- =77.1408 rd. (8) KO=rsin0=lO.595 rd. .*. 77.1408 rd. is the length of the fence, and 10.595 rd.the distance from the center. PROBLEM 383.A circle containing- one acre is cut…
Arithmetic · Geometry
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