A complete and practical solution book for the common school teacher (1899)
Fairchild, J[ohn] T[heodore] [from old catalog] · Crawfis College, Ohio, The author · leaf 236
t ABCD represent the trapezoid. (2) DC=24, AB=36, CB=AD=10. (3) AS = EB=(36—24)^-2=6. (4) Now, CEB is a right triangle. (5) EC=VCB2—EBa=8. .*. 8 is the width of the trapezoid. PROBLEM 440.The sides, a=6, 6=4, c=5 and d=Sy of a trapeziumcircle, being given, find the area of the trapezium. Solution.… … fk;. in PROBLEM 441 What is the edge of the largest cube that can be cut from a hemi-sphere 20 in. in diameter? Solution. (1) Let ALB be the hemi- sphere, and DE the in-scribed cube. (2) ES = ;r, the e6ge of the cube. (3) SP=OP: +*• °r 2 (4) OF = 10 in., ESO is a right triangle. (5) 0?2 = OP2+SP2.…
Arithmetic · Geometry
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