Hatton, Richard G · London, Chapman & Hall ld. · leaf 288
e forward. Putting down the angle equal to the angle between 2 and 3, it comes below 1, and so must be continued up through the eye into 5. This is shown in the solution Solving Problems 253 Fig. 195. We must also have a vanishing parallel forthe lines perpendicular to the mirror. These are 0,… … Fis. 194.—The reflnction of an inclined line. of a vertical plane, containing AC, HF (see Fig. 195,the solution). In the object the top descends as itrecedes; that is, GTF is nearer than IH, and IH is thelower. In the image, however, IH is still the lower,but it is the nearer, and so the top…
Perspective · Drawing
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