ateon a particle placed in a line perpendicular to it through itscentre. Let us suppose the plate divided into very narrow circularrings, drawn about its centre A (fig. 6), and let PQ be atype of such rings. We shall consider the attraction ofeach ring separately, and add them together to iind… … therefore resolve each force alongthat line, and add together theresolved parts so obtained. Now all parts of each ring willbe at the same angular distancefrom OA and will also be at thesame distance from 0. Let theradius AB cut one ring as at Pand Q, where F, Q are points onits inner and outer…
Electricity
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