An elementary treatise on modern pure geometry (1893)
Lachlan, Robert · London, New York, Macmillan and Co. · leaf 91
nglesAIM, HCG are similar. Therefore IM\AI=GC: GH. But GC= GI. HenceAI.IG=IM. GH, that is .ff^_sp = 2Rr. Ex.4. Show that SIi^=R^ + 2Rr^. Ex. 5. If / be the in-centre of the triangle ABC, and if AI cut BC in Xand the circumcircle in G, show that GP=GX.GA.Ex. 6. If -D be the middle point of BC, P the… … Let L, M, Nhe the points of contact of the inscribed circle with the sidesof the triangle. Let D be the middle point of BC, and P the foot of theperpendicular from A. Let the line joining A to the centre of the inscribedcircle cut BC in X, and let XL be the other tangent drawn from X to thiscircle.…
Geometry
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