An elementary treatise on modern pure geometry (1893)
Lachlan, Robert · London, New York, Macmillan and Co. · leaf 96
umcentre, and K the symmedian point of thetnangle ABC. Draw SX, SY, SZ perpendicular to the sides BC,CA,AB, and let them meet the circle described on SK as diameterin the points A, B, C. The triangle ABC is called Brocards first triangle. THE BROCAED CIRCLE. 79 Let BA, GB meet in fl. We shall find… … Therefore, since the angles BXA, GYB are right angles, thetriangles BXA, GYB are similar. Therefore the angle BAX isequal to the angle GBY, that is the angle ilBS. Therefore thepoint D, lies on the circle circumscribing the triangle ASB.Similarly we can show that BA meets AG on the Brocardcircle,…
Geometry
Internet Archive · Cornell University Library · Public Domain Mark 1.0. Free to use for anything.
