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The Decorator's assistant (1847)

[London : W. Gibbs] · leaf 203

An illustration from The Decorator's assistant, 1847, leaf 203
ea of the circle by .7854, andtake the square root of the quotient, which willbe the diameter. Example.—What is the diameter of a circle,the area being 176.715 square feet? .7854) 176.715 (225.15708 1963515708 3927039270 225 (15 = diam.1 [required. 25) 125125 PROBLEM XIV. To find the area of a… … 2) 1098.0 549 = area required. PROBLEM XV, To find the area of the segment of a circle. Find the area of the sector a d c b a, or thatof A D c E F A, by the preceding problem, ac-cording as the area of the less or greater seg-ment is required. Find the area of the triangle a c d, formedby the chord…

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