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The Decorator's assistant (1847)

[London : W. Gibbs] · leaf 203

An illustration from The Decorator's assistant, 1847, leaf 203
2) 1098.0 549 = area required. PROBLEM XV, To find the area of the segment of a circle. Find the area of the sector a d c b a, or thatof A D c E F A, by the preceding problem, ac-cording as the area of the less or greater seg-ment is required. Find the area of the triangle a c d, formedby the chord… … Example 1.—What will be the area of theless segment a c b a, the radius d a being 20inches, the chord a c 22.42 inches, the lengthof the arc a b c 24.43 inches, and the perpen-dicular D G 16.56 inches ? 24.4320 2) 488.60 244.3 sq. in. = area of the sector a b c d a. 22.4216.56 1345211210134522242…

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