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The Decorator's assistant (1847)

[London : W. Gibbs] · leaf 207

An illustration from The Decorator's assistant, 1847, leaf 207
e tenon is to be, inorder to make them fit each other.(To be continued.) No. 25.—Vol. I. 194 THE DECORATOR S ASSISTANT. {Concluded from page 190.) PROBLEM XVI. • To find the area of a ring included betweenthe two circumferences of two concentriccircles. 1. Multiply half the sum of the… … 3.14159 72 6283182199113 226.19448 = circumf. a b c d a. 3.1415940 125.66360 = circumf. e f g h e. 226.19448125.6636 2) 351.85808 175.92904 = half sum of two circumf. 7240 2) 32 16 = half difF. of the two diam. 175.9290416 2814.86464 sq. in. = area. Example 2.—The diameter a c is 30 inches,and the…

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