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The Decorator's assistant (1847)

[London : W. Gibbs] · leaf 207

An illustration from The Decorator's assistant, 1847, leaf 207
25 125 50 625 = F G. .7854 392701570847124 490.8750 = area of circle e f g h a, 706.86490.875 215.985 sq. in. = area of ring. Example 2 is done by the following rule :—Find the areas of tlie two circles separatelythen the difference of these areas gives thearea of the ring. PROBLEM XVII. To find… … 2. Multiply continually together the twodiameters a b, c d, and the number 11. Dividethe last product by 14, and the quotient will bethe area nearly true. Example.—What will be the area of theellipse A D E c A, its transverse a b being 15feet, and its conjugate c d 10 feet?

Design · Decoration and ornament · Art

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