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Elements of analytical geometry and of the differential and integral calculus (1866)

Davies, Charles, 1798-1876 · New York, Barnes & Co. · leaf 153

An illustration from Elements of analytical geometry and of the differential and integral calculus, 1866, leaf 153
0 (1.) ^^ sin (a-a) = ^^; and, . . . (2.)A -^ B = A -{- B ... (3.) J>y substituting for B^ B -y/^^ and for B. ^^/TTT,we have, for the hyberbola, -l^ tan a tan a—J5= 0 .... (1.)AB sin (a- a) = AB , . . (2.) and, A - B = A - B , (3.) *■ Interpretation. Equation (2).—Construct a rectangle on the… … lelograra CGJPJI, is equalto ^i?sm(a_ a) = AB,hence, tlie whole parallelo-gram is equal to the wholerectangle. Therefore, theparallelogram formed bydrawing tangents at thefour vertices of conjugatediameters^ is equivalent to the rectangle formed by drawing tangents through thevertices of the axes.…

Geometry, Analytic · Calculus

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