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Elements of geometry : containing books I to III (1886)

Smith, J. Hamblin · Toronto : W.J. Gage · leaf 107

An illustration from Elements of geometry : containing books I to III, 1886, leaf 107
Thus the area of the irregular polygon ABODE is equalto the sum of the areas of the triangles ABE, EBD, DBC. II. Tin polygon may be co verted into a single triaoj i qua! <• It ABODE be a pentagon, we can convert it into anequivalent quadrilateral by the following pro … Join l,l> and draw CF parallel to BD, mooting ED pro-duced in /•. and join BF. Then will quadrilateral ABFE» pentagon ABODE. For . BDF .!:<!>, on Bame base BD and betweensum- parallels. If, then, from the pentagon we remove a BCD, and add BDF to the remainder, we obtain a quadrilateral…

Geometry

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