Davies, Charles, 1798-1876 · New York and Chicago, A. S. Barnes and company · leaf 66
es AO and BO, meet-ing at the point 0. From O,let fall the perpendiculars OD,OE, OF, on the three sides ofthe triangle—these perpendiculars will be equal to each other. For, in the two right angled triangles DAO and FAO, we ha/e the right angle D equal the right angle F, the angle FAO equal to DAO,… … 66 GEOMETRY Problems In a similar manner, it maybe proved that OE and OD arcequal. hence, the three per-pendiculars, OD, OF, and OE,are all equal. Now, if with O as a centre,^and OF as a radius, we describe the circumference of a circle, it will pass through the pointsD and E. and since the sides…
Geometry · Plane trigonometry
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