Davies, Charles, 1798-1876 · New York and Chicago, A. S. Barnes and company · leaf 97
gle CEB (Ax. I) : hence, the«ide CB is equal to CE (Bk. I. Th. vii.) Now, in the triangle ABE the line CD is drawn parallelto BE: hence, by the last theorem, we haveAD : DB : : AC i CE,and by placing for CE, its equal CB, we haveAD : DB : : AC : CB. THEOREM XV. Equiangular triangles have their… … BOOK IV. 97 Proportions of Triangles. For, on the sides of the larger triangle DEF, make Dlequal to -AC and DG equal to AB, and join IG. Then thr>two triangles ABC and DIG, having two sides and the in-cluded angle of the one equal to two sides and the includedangle of the other, each to each,…
Geometry · Plane trigonometry
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