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Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)

McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 148

An illustration from Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students, 1881, leaf 148
Y. 119 Cor. Hence, if from the vertex of a triangle two straightlines be drawn equally inclined to the sides, one meeting the base,and the other the circumscribed circle, the rectangle under themis equal to the rectangle under the sides. For AP.AD = AB. AG. VI. B is a particular case of this… … angle, and draw ED, making the angle BED equal to an angle inthe given segment ACB, and meeting the circle ABD in D. Join AD. This is the required line. For the quadrilateralCBED is clearly circumscribable by a circle, and therefore AC.AD = AB.AE. q.e.f. 159. Given the rectangle under the sides,…

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