Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)
McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 161
Therefore BF : FC :: BD : CG :: f^/ JJ) (ZM : CG) … Fig. 3. But DA : Off :: ^4^ : EC, since the triangles A ED and 0#£are similar. Therefore BF : .FG f.£0 : DA) U^ : jECJ\and therefore CF. BD . AE = FB. DA . EC,or the solids under the alternate segments are equal. Q. e. d. 1ST.B. In speaking of a transversal cutting systems of straightlines, I shall…
Geometry
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