Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)
McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 187
. … Also, clearly, {4 . Z(?(72)} = {M. LGCD],and {Z\ iTOCJZ} = {M. NBCH). Therefore {M. LGCD} - {M. NBCH}. Therefore (see 187, N.B.), LM and MN form one straight line. Q. E. D. 194. The straight lines joining the opposite angles ofany hexagon described about a circle pass through the samepoint.…
Geometry
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