Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)
McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 243
, (189). Therefore [AHCB] = [ACKB], and therefore … Fig. 2.AB.HC : AH.CB :: AB.CK : AC. KB,or, alternately, AB.HC : AB.CK :: AH.CB : AC. KB. 245.] AND IN MODERN GEOMETRY. 215 Therefore HC : CK :: AH : KB, or CH : HA :: CK : KB, but AC and CB are equal; therefore HA and KB are also equal. Q. E. D. Next, by polars, Fig. 2. Produce 6rZ) and EF to meet…
Geometry
Internet Archive · Wellesley College Library · Public Domain Mark 1.0. Free to use for anything.
