Smart, Edward Howard · London : Macmillian and Co. · leaf 92
Fig. 29. Let CA cut the polar of A in M.Then, since AMBN is cyclic, CM . CA = CB. CN.But CM . CA = square of radius; .*. CB. CN = square of radius;.. AN is the polar of B. §4. Salmons Theorem. The distances of two points from the centre of a circle areproportional to the distances of each from the… … Fig. 30. Let OT, the parallel through O to QL, cut SPL in T.PK, PN be perpendicular to KX and SO respectively.Then SX . SO = square of radius = SP. SL. Also, since OTPN is cyclic, SN . SO = SP . ST ; Let SP SXso SL and also ;ST SP SX- SN NX PK SO SL- ST LT OQ § 5. Conjugate Points and Lines. Def. a…
Geometry, Projective
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