Laurence, Lionel · London, School of Optics · leaf 187
Now/2 is mea-sured from E2, which is -8 cm. from B. Therefore the distance of the imagefrom the second surface of the lens is 12-8 - -8=12 cm. The calculation forthe corresponding thin lens would be l//2=l/8- 1/20, whence/2=13-33 cm.,and since both surfaces are considered coincident with the… … Fig. 196. Fig. 197. Planes of Unit Magnification.—The symmetrical points Sx and S2 (Fig. 196)lie on the principal axis at a distance equal to 2F measured from Ex anteriorly,and from E% posteriorly; they mark the symmetrical planes. An object-pointA in the one symmetrical plane has its image A in…
Optics
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