_ _ 7. . r .a b •> so that a = ak, b = bk, ...The relation between a,b, . . will be expressed by an equationwhich must be homogeneous, for we could not have an expression inwhich lines would be added to rectangles, and both to cubes. Sub-stituting, then, ak, bk, . . for a, b, . . , we shall find… … Let A, B, C be the three given st. lines. It is required to find a fourth ji^oportiotKd to them. Draw the lines DE, DF. Take DG = A, GH = B, and DK = C. Join GK, and draw HL || to GK. Then KL is a fourth propoi-tioual to A, B, C. Since GK is || to HL ; .. DG:GH = DK:KL. (TIL, 2.) Henee A: B = C:KL,…
Geometry · Geometry, Plane
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