N perpendicular to MRN the normal at R; let QM alsoperpendicular to the normal meet it in M . Then RP = RQ,QM = PM, and the triangles QRN and QRM are similar. 34] REFRACTION AT PLANE SURFACES. 57 Therefore Qtf=Qtf_ PM RP PM M RQ construction. Hence the perpendiculars onthe normal at R from P and… … or QRN=<f>, the angle of refraction. * (3) The following construction is sometimes useful. WithR the point of incidenceas centre and radii RA, RBsuch that RB = fjiRA, de-scribe two circles, fig. 38.Draw the incident ray PRcutting the circle with radiusRA in P. Through P drawLPQ normal to the…
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