[Coffin, John Huntington Crane], 1815-1890. [from old catalog] · New York, D. Van Nostrand · leaf 31
90°-Z) tan £(90° + Z) or that —log tan i (90°—Z)=log tan £ (90°+ i). Hence we have, by reducing, Z> = 7915,.70447 log tan (45° + £Z) tan C. (13) Note.—Problem 5 may be more readily solved, and equation (13) obtainedby aid of the Calculus. In Fig. 1, suppose c a to be an element,or infinitesimal… … mercators sailing. 25 By articles 5 and 10, using the notations of the Calculus, we haved X = cos Odd d p = tan C d Xd D = sec Ldp = tan (7 sec XdX,in which C i3 constant. By integrating the last equation between the limits X = 0 and X = Z, weshall have r LX = tan C\ sec X d X, the whole difference…
Navigation · Nautical astronomy
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