On some geometric properties and applications of conformal rational transformations in a plane (1912)
Renich, Mary Emma · leaf 66
= 1 as its center. This circle, like all others,passes through the circular points at infinity. Since there arefour imaginary solutions of these equations at infinity and both(3) and (4) have but two infinite points, the two curves musthave coincident intersections at these points; that is, they… … 29. (h - a) z2 + U -/3 ) 2 - V = 0 . (6) Substituting in (6) the values of our complex numbers, it becomes(a3 + ib3 - aQ - ibQ)(x + i y)a + (a4 + ib4 - &1 - ibx)(x + iy) - (a2 + ib2) = u + iv - 0,where u = (a3 - a0) x2 - (a3 - aQ) y2 + 2 x y (bQ - b3) + (a4 - ajx - (b4 - bx) y - a2 = 0, (?) ▼ =…
