Carhart, Henry S. (Henry Smith), 1844-1920 · Boston : Allyn and Bacon · leaf 44
ement. — Let the particle be at the pointB in the circle of reference (Fig.16). The displacement is the lineOC. The acceleration toward A f) the centre is ~~r, since the par- T ticle is moving uniformly aroundthe circle. The problem is toresolve this centripetal acceleration into two rectangular… … Fig. 16. 34 MECTIA NTCS. /> 4?r2 /= - Call the two displacements along the two axes a: and yrespectively ; then Therefore fx = cos 0 — ?, sin 6 — ^.r 7* 4-7T2 47^ y- The first component varies as # and the second one asy ; or the two components of the centripetal accelerationare proportional to…
Physics
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