Bailey, Frederick H. (Frederick Harold), 1865- · Boston, London, Ginn & Co. · leaf 293
2, theline of intersection of this plane with the plane XOY. ThenP1P2 and M1M2 are the respective hypotenuses of the righttriangles PiSPg and MiRMo. Therefore Pi P2 = S P2 + S Pi = ivuvi;+sp; = RM2+ RMr+SPi- (xi - X2)^ + (yi - y,f + (zi - Z2)^for RM2 = X2 — Xi, RMi = yi — ya, and SPi = Zi — z^.Or,… … Fig. 6. THE POINT. 279 To find X, draw PiNi, PN, and P2N2 parallel to OX andmeeting the plane YOZ at Ni, N, and Ng, respectively. In theplane determined by the parallel lines PiNi and PgNo drawPiR and PS parallel to NiNN., the line of intersection ofthis plane with the plane YOZ. Then NiPi = Xj, NP…
Geometry, Analytic
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