Bailey, Frederick H. (Frederick Harold), 1865- · Boston, London, Ginn & Co. · leaf 41
is whichlies to the left of — 3 or to the right of + 3. (4) Using values of x which lie between — 3 aud_+ 3, we find thefollowing points of the curvej (-3, 0), (-2, ±|V5), (-1, ±|V8),(0, ±2), (1, ±|V8), (2, ± 3V5), (3, 0). (5) The plotting of the points leaves the shape of the curve… … We have seen that the curve cannot lie to the left of x = — 3 or tothe right of x = + 3. Similarly, we may show that it cannot lie abovey = +2 or below y = — 2. This we do by solving the equation for xWe have, then, X = ± IV4 - y2 = ± 3 V(2 - y) (2 + y). From this it appears that x is imaginary, if…
Geometry, Analytic
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