of hour angle desired = sine of lat. X tan. the tabular value for 38 deg. and 40 deg. is 0.29 inch, (hour number X 15 deg.), the last term being the hour or say 0.15 inch for 1 deg. or 0.12 for 5/6 degree, 3.91 angle of the sun for the given time. 15 deg. for I + 0.12 = 4.03, the height required.… … consideration of, tlJQ difference 0.25 in c h, SUN DIALS: HOW THEY ARE MADE AND USED.
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