Gore, James Howard, 1856-1939 · New York, Longmans, Green, and co. · leaf 124
icular to AB. Then (by 227) AC2 = AB x AD, and Adding, we have BC2 = ABx BD. AC + BC =ABx (AD + BD)= AB x AB = AB2. * This proposition is called the Pythagorean Proposition because it issaid to have been first given by Pythagoras (born about 600 B.C.). § 265.] AREAS OF POLYGONS. Ill But AC , BC~,… … L E Construct upon AC, the square ACGF, upon CB, CBKff,and upon AB, ABED. Draw CL perpendicular to DE, and join FB and CD. The triangle FAB is one-half the square ACGF, having thesame base AFand the same altitude AC. The triangle DAC — 1ADLN, having the same base ADand the same altitude AN. The…
Geometry
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