Gore, James Howard, 1856-1939 · New York, Longmans, Green, and co. · leaf 52
iangle BOC, for the same reason, NQ = ± CO and isparallel to CO. Therefore (by 28) RM is equal to and parallel with QN. In the triangle ACB (by 112), RQ = 1 AB and is parallelto it. In the triangle AOB (by 112), MN= i AB and is parallelto it. Therefore RQ = MN said is parallel to it. Hence the… … 40 PLANE GEOMETRY. [BK. I.
Geometry
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