Creighton, William Henry Paul, 1859- · New York, J. Wiley & sons; [etc., etc.] · leaf 174
e areabetween the adiabatic and the base is in each case equal to the heatin the gas. At a the heat in the gas is KVTX) at d the heat in thegas is Kv(Tx+dT). The work done badc = PdV. Let c/# = heatadded. Then KVTX +dH = Kv(T1 +dT) +PdV dH=KvdT-PdV. To derive the formula dH = KpdT-YdP. Let ade ...… … Fig. 102. KvdT+bafg = KpdT. The path of the fluid is from a to d, however. The heat in| the gas at d and / is the same since those points are on thesame isothermal. To reach the point d from / the gas must becooled or heat must be subtracted equal to the area dcgf. Since df is an isothermal,…
Steam-engines · Heat-engines
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