Inside Out Library · Explore

The steam engine and turbine; a text-book for engineering colleges (1911)

Heck, Robert Culbertson Hays, 1870- · New York, D. Van Nostrand company · leaf 350

An illustration from The steam engine and turbine; a text-book for engineering colleges, 1911, leaf 350
. (172), or Fi = FoUosa -f y-cos2Q;j, As to F2 and F3, their resultant Fb = F3 — F2 (see Fig. 157) is thefree counterforce whose horizontal component partly balances Fi.This component is H = Fb cos a. By subtraction, we get the horizontal shaking force to be R Se. = {Fq — Fb) cos a + y- Fq COS 2 a… … Fig. 191. — Shaking-force Components. the radius of the circle to {Fq — Fb) without changing the distance ofpoints on the curve E1E2 from the line GH. Thus, in Fig. 191 I, thediagram on AB is drawn with Fq as radius, and gives i^i; which wouldbe identical with *Sh if M3 were made equivalent to Mi,…

Steam-engines · Steam-turbines

Internet Archive · Library of Congress · Public Domain Mark 1.0. Free to use for anything.

More pictures from The steam engine and turbine; a text-book for engineering colleges

More like this