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Trigonometria (1658)

Newton, J. · leaf 16

An illustration from Trigonometria, 1658, leaf 16
enfe of an arch comoofed of the archgiven, andof half his complement to a femicircle is given alfo. Forbythis Propofition AGequal to A C and E F is alfo equal to the fquare of A F, the fubtenfe of the arch E D F, andB A the half complement of p p F to a Semicircle, and the Root is AY, the… … a Trigonometria Britannica. Perpendicular to the right Sine C F; and H F (for the fame reafon) isdtt^^flg^tbealff^ £ right Sine of its complement are equal to the ^A™l*tbefirft Di*granof thk Cbapter)¥D the verfed fine of C D and AF are equal to AD therefore the Radius and fine complement of an arch…

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