iy8 ELEMENTS OF MACHINERY. AF = V2 AE — V2 l cos w, if l — length of beam. We had 1 CD — m DB — m AF = m — cos w, and BE — DF — l sin zv. Therefore, I 1 CF — DF -|- CD — l sin zv -|- m — cos zv — ( 2 sin zv -f- m cos w) 2 2 P … Frictional Angle of a Beam. Friction on Inclined Plane. / l AF = m CF ; therefore, — cos w — — m ( 2 sin w -f- m cos w) , 2 or • cos zv = 2 m sin w + m m cos w, divide equation by cos zv. sin zv sin zv 1 — -mm 1 ~ 2m 1- m m , or — tan zv — , cos zv cos zv 2m which gives for the known coefficients m…
Brewing · Malt
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