Hatfield, Robert Griffith, 1815-1879. [from old catalog] · New York & London, Wiley and Putnam · leaf 66
int of division in da, draw lines to I; then a curve traced through the points ofintersection, o, o and o, will be that of a parabola. 127, a.—Another method. Let m l, {Fig. 93,) be the axis andheight, and d d the base. Extend m I, and make I a equal to mI; join a and d, and a and d ; divide a d… … p \ -i i o ^ Fig. 94. 128.— To describe an hyperbola by intersection of lines.Let r 0, {Fig. 94,) be the height, p p the base, and n r the trans-verse axis. (See Fig. 79.) Through r, draw a a, parallel to pp ; fromp, draw ap^ parallel to r 0; divide ap andp 0, eachinto a like number of equal parts;…
Carpentry · Architecture
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