Snyder, Virgil, 1869-1950, Sisam, Charles Herschel, b. 1879 · New York : H. Holt and Company · leaf 23
lK-2 +iv.2 = 0. (4) The square of the sine of 6 may be found from (1) and (3).Since sin^ ^ = 1 — cos^ 6, it follows that sin2 6 = (Ai^ + ix^ + v,2) {X^ +ix,^ + v.^) - (A1A2 + M1M2 + v,v,Y — (Ai)a2 — XofJ^xf + {lJ^iV2 — M2Vl)^ +(viA2 - V2Ai)2. <5. Point dividing a segment in agiven ratio. Let Pj… … Fig 7. the line P1P2. Then (Art. 2, Th. I) we have P,PA = .T — Xi and PP2\ = X2—x.Hence P^P A : PP2 \ = x — Xi : x^ — x^ m^ : wij. Art. 6] POINT DIVIDING A SEGMENT 9 On solving for x we obtain x = —^-—! =, (6) mi + m2 c 1 1 „ m2!/i + mii/2 Similarly, y = ; . ~ mi + m^ It should be noticed that if…
Geometry, Analytic
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