A complete and practical solution book for the common school teacher (1899)
Fairchild, J[ohn] T[heodore] [from old catalog] · Crawfis College, Ohio, The author · leaf 167
FIG. 23. (3) OD=VBOa—BD*=7; DC = OC—OD, or 18. (4) BC = VBD*+DCa=30. (5) AB=VACa—BC»=40. ABC is a 30, 40 and 50 triancle. 152 FAIR CHILDS SOLUTION BOOK. … FIG. 24. Second Solution. (1) Let ABC be the right tri- angle. (2) Construct the square KC upon its hypothenuse, andfrom the corners of thissquare let fall the perpen-diculars KE, LH and BG,this forms three new tri-angles, equal to ABC, anda square GE. (3) Now, through the corners of the square KC,…
Arithmetic · Geometry
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