A complete and practical solution book for the common school teacher (1899)
Fairchild, J[ohn] T[heodore] [from old catalog] · Crawfis College, Ohio, The author · leaf 207
awn to intersect thecircumference construct-ed on AB as a diameter,and these points F andE be joined with B; theywill be radii that will de-termine rings of equalarea. (3) BT is the radius of the aperture, or 3 in., which subtracted from 16 in. leavesAT=13 in. (4) The area of the stone=1627r=2567r.… … FIG. 72. (8)(9) (10) (11)(12)(13)(14) 173|7r—82j7r=91^7r, area of the stone after the secondgrinds. Dividing the area of a circle by tt and extracting thesquare root give the radius. AB = V(256^T=1,6 in. HB = V(73i»-Hr) =13.178 in. SB = V(173i7r-Hr):=9.557 in. .-. The first man grinds off…
Arithmetic · Geometry
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