A complete and practical solution book for the common school teacher (1899)
Fairchild, J[ohn] T[heodore] [from old catalog] · Crawfis College, Ohio, The author · leaf 229
ft. (5) VSB~*+BT* = V802+80*= 113.13 ft.=ST. (6) SE=VSDa+DE2, orV502+502=70.71 ft. 214 FAIRCHILDS SOLUTION BOOK. (7) (8) (9) (10) (ID(12)(13) (14) In the scalene tri-angle STE, EK isits perpendicular,and now we willfind SK and KT bya well known theo-rem in geometry. TS : TE + ES:: TE—ES : KT—SK,… … FIG. 99. KE = VKT2—ET2=49.6 ft. Area of STE^jSTx EK = 2805.376 sq. ft. The area of SBT = 3200 sq. ft, and area of EDS = 12500 sq. ft.Therefore, the area of DSBTE = area of ABCD = 7255.375 sq. ft..*. AB, the side of the square garden = 85-f- ft. PROBLEM 425.A square farm contains 40 acres. It is…
Arithmetic · Geometry
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