A complete and practical solution book for the common school teacher (1899)
Fairchild, J[ohn] T[heodore] [from old catalog] · Crawfis College, Ohio, The author · leaf 247
all. (2) OB=r=3, OF=CD= R, the radius of theauger bit, and CB=^. (3) ThenCT)2=R2 = (2r—x)x, and CO =r—x. (4) The volume removed equals a cylinder, ra-dius R, and height 2(r—x), together with two segmentsof the ball of height x, and radius R. (5) The volume of the cylinder is 2(2r—x) XTr(r—x). (6)… … FIG. 121. MENSURA TION. 233 (9) &JZ)=x—r=rf% . . . (3)._ (10) .-. R* = (2r—x)x=r*(l—jf2) . . . (4). (11) 2R=2rV (1—iV2) =6V (1—if 2), diameter of auger bit, or 3.6496 in. PROBLEM 463.A blacksmith had an iron ball,Which he did a bullet call;He found out, by some nice trick,It was exactly one…
Arithmetic · Geometry
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