Skene, Norman L. (Norman Locke), 1878-1932 · New York : The Rudder Pub. Co. · leaf 21
the product of its base byits altitude, thus the area of the triangle ABC (fig. 5) is equal to Yi (ACX Bm). The center of gravity of the triangle is at p, the point of inter-section of Ac and Cn, n and o being the middle points of AB and BC re-spectively. lO EI.EMKNTS OF YACHT DESIGN The area of a… … FIG. 6. X Dn). The center of gravity is on a line connecting the centers of thecomponent triangles. In fig. 7, m and n are the centers of the triangles.\BD and BCD, while o and p are the centers of the triangles ABC andACD. Draw lines mn and op. Their point of intersection, x, is then tin-
Shipbuilding · Yachts
Internet Archive · Cornell University Library · Public Domain Mark 1.0. Free to use for anything.
