/ equilibrium of the three J; c ff rods as one system. Now the directions of the forces P, Q, B meet in 0 thecentre of the circumscribing circle;—and since P, Q, M are inequilibrium we must hare P: Q:B = smQOB: sinBOP: sinPOQ = smA : sinB: ainG=a : b : c, which proves the first part of the problem.… … 52 OF FORCES ACTING IN ONE PLANE. Since AB is in equilibrium under the action of the threeforces *Si, T, B, the directions of these forces must meet in a-point C suppose—and since B bisects AB at right angles weeasily infer that 7= GAB= CBA=y, and 8=T. Simi-larly the strain at G is equal to 8 or…
Mechanics
Internet Archive · Cornell University Library · Public Domain Mark 1.0. Free to use for anything.
