International Library of Technology · Scranton, International Textbook Co. · leaf 270
be 25 amperes,because each lamp will take J ampere. Using formula 5, we have A = 21.6 X 1,050 X 2510 = 56,700 cir. mils. Ans. A No. 3 B. & S. wire would likely be used. Example 2.—A dynamo A, Fig. 46, supplies current through thefeeders b, c to the feeding-in point a. From this point lamps are… … exceed 15 volts, of which 13 volts is to be in the feeders and 2 volts inthe mains; required, (a) the cross-section and gauge number of thefeeders b, c; (b) the cross-section and nearest gauge number ofthe mains d, e; (c) the cross-section and nearest gauge numberof the mains/, g. Solution.— 150…
Electrical engineering
Internet Archive · Boston Library Consortium · Public Domain Mark 1.0. Free to use for anything.
![An illustration from [Electric engineering.], 1902, leaf 270](https://img.insideoutlibrary.com/img/1024/ia-electricengineer03inte-270-156.webp)
![An illustration from [Electric engineering.] (1902)](https://img.insideoutlibrary.com/img/200/ia-electricengineer04inte-315-138.webp)
