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Elements of analytical geometry and the differential and integral calculus (1856)

Robinson, Horatio N. (Horatio Nelson), 1806-1867 · Cincinnati : J. Ernst · leaf 127

An illustration from Elements of analytical geometry and the differential and integral calculus, 1856, leaf 127
n equation (A) becomesa:3—13ar+2=^0,and a solution of this equation gives three other points. And thus we may proceed, assigning different values to y, anddeducing the corresponding values of x, as appears in the fol-lowing table, commencing at the origin of the co-ordinates,where y=0, and varying… … Wheny=0. then will x—-{-l. +3. —4. y=—5 a;=+1.66 +2.477 —4.14 2/=—6.0388 a;=+2.0814 +2-0814 —4.1628 Taking z/=0, a solution of theequation 2/=a;3—13a;+12, gives thethree points a, a, a, on the axis of X.Then taking 2/=5, and a solutiongives three points b, h, h, on a lineparallel to the axis of X,…

Geometry, Analytic · Calculus

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