International Correspondence Schools · Scranton, Pa. : The Colliery engineer co. · leaf 559
hes will give the distancefrom the frog point f to the frog point //: 3 feet 7 inches= 43 inches, 43 X 9 = 387 inches = 32 feet 3 inches. Ac-cordingly having located the point of frog /, we mark acorresponding point on the nearest rail of the opposite track.From this jicint we measure along the… … TRACK WORK. 1145 be used, the distance between the frogs is found as fol-lows : As the No. 7 frog spreads 1 inch in 7 inches, and the No. 0frog 1 inch in 9 inches, the two will together spread 2 inchesin 7 + !» =10 inches, or 1 inch in S inches. Now, if the railsto be united are 3 feet 7 inches, or…
Railroad engineering
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