Let ABC be a tri-angle having AC >AB: then shall theangle ABC he > theangle C. From AC cut offAl) equal to AB-,and draw BJD. T:\ien,.AB = AI),.. the angle ABI) =the angle ABB; but the angle ABBis exterior to the Tri-angle BCB, and .*.< the angle C; , •. the angle ABBalso > the angle C;… … Let us now suppose a TriangleABC, in which the bisector of theangle BAC is not an axis of sym-metiy. Then the contra-positiveform of the theorem of § 162 tellsus that AB is not equal to AC,that the angle B is not equal tothe angle C, and that the bisectorAD of the angle A is not perpen-dicular to…
Euclid · Geometry
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